I'd like to call the link's category in link.html.
However, when I use <%Category%>, I get "Unknown Tag: 'Category'".
Any ideas?
However, when I use <%Category%>, I get "Unknown Tag: 'Category'".
Any ideas?
Aug 17, 2006, 2:15 PM
Enthusiast (700 posts)
Aug 17, 2006, 2:15 PM
Post #3 of 12
Views: 3981
Unless you have created one, there shouldn't be one. You can use <%GT::Template::dump%> to see what you do have. Otherwise, you can easily create a global like:
http://www.gossamer-threads.com/...i?post=196185#196185
Hope this helps,
- Jonathan
http://www.gossamer-threads.com/...i?post=196185#196185
Hope this helps,
- Jonathan
Aug 17, 2006, 2:36 PM
User (137 posts)
Aug 17, 2006, 2:36 PM
Post #4 of 12
Views: 3981
Thanks. I did the Dump, and you are right, there is no Category variable available. Are you able to expound upon the global code to achieve what I want? I tried Alex' global at the end of the thread you suggested, and just got a linked "Home :" return.
Ideally, I could get a linked or unlinked (it doesn't matter) "Category > Subcategory > Subsubcategory" return for the applicable link.
Aug 17, 2006, 3:03 PM
Enthusiast (700 posts)
Aug 17, 2006, 3:03 PM
Post #5 of 12
Views: 3978
Try this:
sub {
my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my ($full_name) = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
require Links::Build;
my $title = Links::Build::build('title_linked', $full_name);
return $title;
}
I haven't tested it, but it should work.
- Jonathan
Code:
sub {
my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my ($full_name) = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
require Links::Build;
my $title = Links::Build::build('title_linked', $full_name);
return $title;
}
I haven't tested it, but it should work.
- Jonathan
Aug 17, 2006, 3:09 PM
User (137 posts)
Aug 17, 2006, 3:09 PM
Post #6 of 12
Views: 3985
Very good, thank you. This returns a linked string, for example "Home: Category: Subcategory" where Home and Category are linked. Is it possible to:
1. Have " > " be used instead of ": "
2. Either link the whole string (i.e., including "Subcategory") or unlink everything?
Thanks! I owe you a beer!
EDIT: I changed the global to:
Code:
sub { my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my ($full_name) = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
return $full_name;
}
And that gives me "Catgegory/Subcategory"
That works fine for me, unless there is an easy way to link all of Home, Category and Subcategory using ">"
Thanks again!
Aug 17, 2006, 3:28 PM
Enthusiast (700 posts)
Aug 17, 2006, 3:28 PM
Post #7 of 12
Views: 3969
I think you can call format_title from your links.html template (assuming Category is your global name).
<%Links::Utils::format_title($category, separator => $crumb_separator, no_escape_separator => $no_escape_crumb_separator, include_home => 1, link_type => 2)%>
- Jonathan
<%Links::Utils::format_title($category, separator => $crumb_separator, no_escape_separator => $no_escape_crumb_separator, include_home => 1, link_type => 2)%>
- Jonathan
Aug 17, 2006, 3:39 PM
User (137 posts)
Aug 17, 2006, 3:39 PM
Post #8 of 12
Views: 3971
My preference would be to have the display the same as on the New and Cool pages:
Code:
<%Links::Utils::format_title($title_loop, separator => $category_separator, no_escape_separator => $no_escape_category_separator, include_home => 0, link_type => 1)%>
Right now my global is pulling the result "Category/Subcategory". So I guess I need to return whatever the equivalent of $title_loop. Maybe this was what your initial global suggestion did? I will try it out.
EDIT - That didn't work. What is the $title_loop variable referring to in the above? My global should grab that equivalent field.
Aug 17, 2006, 4:05 PM
Enthusiast (700 posts)
Aug 17, 2006, 4:05 PM
Post #9 of 12
Views: 3957
try something like this:
sub {
my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my ($full_name) = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
require Links::Utils;
my @titles = split(/\//, $full_name);
return (Links::Utils::format_title(@titles, separator => ">"));
}
That MIGHT work... (will be back to check in a few hours)...
- Jonathan
Code:
sub {
my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my ($full_name) = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
require Links::Utils;
my @titles = split(/\//, $full_name);
return (Links::Utils::format_title(@titles, separator => ">"));
}
That MIGHT work... (will be back to check in a few hours)...
- Jonathan
Aug 17, 2006, 4:11 PM
User (137 posts)
Aug 17, 2006, 4:11 PM
Post #10 of 12
Views: 3955
Unfortunately, I get the following error:
Can't use string ("Distributors & Resellers") as an ARRAY ref while "strict refs" in use at /var/home/xxx/wiredbiz.com/cgi-bin/links/admin/Links/Utils.pm line 492.
"Distributors & Resellers" is one of the main categories in our DB.
Aug 17, 2006, 8:10 PM
Enthusiast (700 posts)
Aug 17, 2006, 8:10 PM
Post #11 of 12
Views: 3955
Just got home...
This should do the trick:
sub {
require Links::Utils;
require Links::Build;
my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my $full_name = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
return (Links::Utils::format_title(Links::Build::build_title($full_name), separator => " > ", link_type => 1, ));
}
Good Luck!
- Jonathan
This should do the trick:
Code:
sub {
require Links::Utils;
require Links::Build;
my $tags = shift;
my $catid = $DB->table('CatLinks')->select('CategoryID', { LinkID => $tags->{ID} })->fetchrow;
my $full_name = $DB->table('Category')->select('Full_Name', { ID => $catid })->fetchrow;
return (Links::Utils::format_title(Links::Build::build_title($full_name), separator => " > ", link_type => 1, ));
}
Good Luck!
- Jonathan