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Show record if 'status' field = "active"?

Jun 7, 1999, 11:21 AM
mike1
User (91 posts)
Jun 7, 1999, 11:21 AM
Views: 3558
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Show record if 'status' field = "active"?
Where could I insert code to only view a record if a given field is set 'active'? For example:

if ($rec{'status'} eq "active"){
display record;
}
Subject Author Views Date
Thread Show record if 'status' field = "active"? mike1 3558 Jun 7, 1999, 11:21 AM
Thread Re: Show record if 'status' field = "active"? 		Eliot 3462 Jun 7, 1999, 11:51 AM
Thread Elio Please do u know to do this !!! SEE PLEASE 		kevinws 6436 May 3, 2004, 1:32 PM
Post Re: [kevinws] Elio Please do u know to do this !!! SEE PLEASE 		LoisC 3324 May 4, 2004, 4:29 PM
Post Re: Show record if 'status' field = "active"? 		mike1 3446 Jun 7, 1999, 4:39 PM
Post Re: Show record if 'status' field = "active"? 		mike1 3424 Jun 7, 1999, 4:50 PM
Post Re: Show record if 'status' field = "active"? 		JPDeni 3465 Jun 8, 1999, 3:47 AM
Post Re: Show record if 'status' field = "active"? 		mike1 3447 Jun 8, 1999, 4:24 AM