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General: Databases and SQL: Re: [hdnguyen3] Sql Query, Help!: Edit Log

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Re: [hdnguyen3] Sql Query, Help!
This should work:

Code:
SELECT CUSTOMER_NAME, CUSTOMER_ID
FROM CUSTOMER
WHERE CUSTOMER_NAME LIKE 'Curie%';

Last edited by:

Paul: Mar 15, 2003, 2:15 AM

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