Gossamer Forum: General: Internet Technologies: Simple PHP problem I'm stuck on.

May 8, 2011, 9:04 PM

Michael_Bray

User (378 posts)

May 8, 2011, 9:04 PM

Post #1 of 3

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Simple PHP problem I'm stuck on.

Hi Guys,

Long time no see! I've been out of the game for a while now. I'm writing a PHP script and I'm having a mental block on a simple PHP problem - Hoping someone could help me with Smile

I need to write a loop that goes up, then back down between 1 and a variable number. I.e. if $v = 5 I need the loop output to be
1,2,3,4,5,5,4,3,2,1,1,2,3,4,5,5,4,3,2,1
I know the solution is going to be simple but for some reason I can't figure it out :-(

Looks like the forums here have gone quiet since I was a regular Frown

Cheers,
Michael Bray

May 8, 2011, 9:25 PM

Michael_Bray

User (378 posts)

May 8, 2011, 9:25 PM

Post #2 of 3

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Re: [Michael_Bray] Simple PHP problem I'm stuck on. In reply to

I’ve got it close but can’t figure it out. I have done:

Code:
<?php 
 
$i = 1; 
$direction = "up"; 
$v = 5; 
 
$loop = 20; 
$l = 1; 
 
while ($l < $loop) 
{ 
 if($direction == "up") 
 { 
      $l++; 
      print $i; 
 $i++; 
      if ($i == $v){ 
          $direction = "down"; 
 } 
    } else { 
        $l++; 
        print $i; 
 $i = $i-1; 
       if ($i == 1){ 
          $direction = "up"; 
 } 
    } 
} 
 
 
 
?> 

But it outputs 1,2,3,4,5,4,3,2,1,2,3,4,5,4 etc
When I need the last numbers to repeat next to each other i.e. 1,2,3,4,5,5,4,3,2,1,1,2,3,4,5
Cheers,
Michael Bray

May 8, 2011, 10:27 PM

Michael_Bray

User (378 posts)

May 8, 2011, 10:27 PM

Post #3 of 3

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Re: [Michael_Bray] Simple PHP problem I'm stuck on. In reply to

Figured it out, if you're interested:

Code:

$i = 1;
$direction = "up";
$v = 5;

$loop = 20;
$l = 1;

while ($l < $loop){

print $i;
$l++;

if($direction == "up"){

if($i >= 4){
$i = 4;
$direction = "down";
} else {
$i++;
}

} else {

if($i <= 1){
$i = 1;
$direction = "up";
} else {
$i = $i - 1;
}

}

}

Cheers,
Michael Bray