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Hello,

I am new to Link SQL PHP and have a problem I could not solve. We translated all templates to php templates. Unfortunately, some of them do not work.

Something like "Warning: Invalid argument supplied for foreach() in
...default_php/link.html on line 17" appears.

That is the code:

16 ...
17 <?foreach($link_cats as $rec)
18 {
19
20 extract($rec, EXTR_OVERWRITE)?>
21
22 <?if (!$link_Title) {?>
23 ...

Any suggestion?

Thanks a million,

Joe
Subject Author Views Date
Post warning line 17 Joe Cool 3959 Mar 22, 2005, 8:25 AM