billy.earney at gmail
Nov 20, 2009, 7:06 AM
Post #3 of 3
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Try looking at the function 'isinstance', so for example
if isinstance(obj, str):
print "object is a string.."
elif isinstance(obj, int):
print "object is an integer.."
-----Original Message-----
From: python-list-bounces+billy.earney=gmail.com [at] python
[mailto:python-list-bounces+billy.earney=gmail.com [at] python] On Behalf Of
mk
Sent: Friday, November 20, 2009 4:10 AM
To: python-list [at] python
Subject: checking 'type' programmatically
Disclaimer: this is for exploring and debugging only. Really.
I can check type or __class__ in the interactive interpreter:
Python 2.6.2 (r262:71600, Jun 16 2009, 16:49:04)
[GCC 4.1.2 20080704 (Red Hat 4.1.2-44)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import subprocess
>>>
p=subprocess.Popen(['/bin/ls'],stdout=subprocess.PIPE,stderr=subprocess.PIPE
)
>>> p
<subprocess.Popen object at 0xb7f2010c>
>>> (so, se) = p.communicate()
>>> so
'abc.txt\nbak\nbox\nbuild\ndead.letter\nDesktop\nhrs\nmbox\nmmultbench\nmmul
tbench.c\npyinstaller\nscreenlog.0\nshutdown\ntaddm_import.log\nv2\nvm\nwork
space\n'
>>> se
''
>>> so.__class__
<type 'str'>
>>> type(so)
<type 'str'>
>>> type(se)
<type 'str'>
But when I do smth like this in code that is ran non-interactively (as
normal program):
req.write('stderr type %s<br>' % type(se))
req.write('stderr class %s<br>' % str(se.__class__))
then I get empty output. WTF?
How do I get the type or __class__ into some object that I can display?
Why do that: e.g. if documentation is incomplete, e.g. documentation on
Popen.communicate() says "communicate() returns a tuple (stdoutdata,
stderrdata)" but doesn't say what is the class of stdoutdata and
stderrdata (a file object to read? a string?).
Regards,
mk
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