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HTTP request error with urlopen
 

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spandanagella at gmail

Jul 2, 2008, 11:52 PM


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HTTP request error with urlopen

Hello ,

I have written a code to get the page source of the google search
page .. this is working for other urls. I have this problem with

import re
from urllib2 import urlopen
string='http://www.google.com/search?num=20&hl=en&q=ipod&btnG=Search'
file_source=file("google_source.txt",'w')
file_source.write(urlopen(string).read())
page_content=file_source.readlines()

Traceback (most recent call last) :
File "C:/Python25/google.py", line 5,in <module>
file_source.write(urlopen(string).read())
File "C:\Python25\lib\urllib2.py", line 124 , in urlopen
return__opener.open(url, data)
File "C:\Python25\lib\urllib2.py", line 387 , in open
response =meth(req, response)
File "C:\Python25\lib\urllib2.py", line 498 , in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python25\lib\urllib2.py", line 425, in error
return self._call_chain(*args)
File "C:\Python25\lib\urllib2.py", line 360, in __call_chain
result = func(*args)
File "C:\Python25\lib\urllib2.py", line 506, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden

Actually urlopen is working for google labs sets page but not for the
google.com and even I have same problem with wikipedia . Please let me know
.. If any one of have any idea about this .

Thank You,
Spandana.

Subject User Time
HTTP request error with urlopen spandanagella at gmail Jul 2, 2008, 11:52 PM
    HTTP request error with urlopen spandanagella at gmail Jul 3, 2008, 7:14 PM
    Re: HTTP request error with urlopen jonas at codeazur Jul 3, 2008, 8:34 PM

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