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String Question

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diffuser78 at gmail

Jun 28, 2006, 8:35 AM

Post #1 of 13 (391 views)
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String Question

mac_string = '001485e55503' (This is the mac address of a computer.)

I am using wake on LAN python script to start computer remote.It uses
format like this ....

s.sendto('\xff'*6 + '\x00\x014\x85\xe5\x55\x03'*16, ('192.168.1.255',
80))

where '\x00\x14\x85\xe5\x55\x03' is the MAC address to be used.

What I do is break the string into 6 parts like this,

str01=mac_string[0:2]
str02=mac_string[2:4]
str03=mac_string[4:6]
str04=mac_string[6:8]
str05=mac_string[8:10]
str06=mac_string[10:12]

and if I use it like this

s.sendto('\xff'*6 + '\xstr01\xstr02\xstr03\xstr04\xstr05\xstr06'*16,
('192.168.1.255', 80))
I get an error

I also tried like this
s.sendto('\xff'*6 + 'mac_string'*16, ('192.168.1.255', 80))

Thiis also didnt work.

Since the MAC adddress are hexadecimal, how should I go about it here.

Please help, every help is appreciated. Thanks

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fredrik at pythonware

Jun 28, 2006, 8:45 AM

Post #2 of 13 (380 views)
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Re: String Question [In reply to]

iainking at gmail

Jun 28, 2006, 8:48 AM

Post #3 of 13 (381 views)
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Re: String Question [In reply to]

diffuser78[at]gmail.com wrote:
> mac_string = '001485e55503' (This is the mac address of a computer.)
>
> I am using wake on LAN python script to start computer remote.It uses
> format like this ....
>
> s.sendto('\xff'*6 + '\x00\x014\x85\xe5\x55\x03'*16, ('192.168.1.255',
> 80))
>
> where '\x00\x14\x85\xe5\x55\x03' is the MAC address to be used.
>
>
> What I do is break the string into 6 parts like this,
>
> str01=mac_string[0:2]
> str02=mac_string[2:4]
> str03=mac_string[4:6]
> str04=mac_string[6:8]
> str05=mac_string[8:10]
> str06=mac_string[10:12]
>
> and if I use it like this
>
> s.sendto('\xff'*6 + '\xstr01\xstr02\xstr03\xstr04\xstr05\xstr06'*16,
> ('192.168.1.255', 80))
> I get an error
>
>
> I also tried like this
> s.sendto('\xff'*6 + 'mac_string'*16, ('192.168.1.255', 80))
>
> Thiis also didnt work.
>
>
> Since the MAC adddress are hexadecimal, how should I go about it here.
>
> Please help, every help is appreciated. Thanks

See http://docs.python.org/lib/typesseq-strings.html

You probably want:

s.sendto('\xff'*6 + ('\x%s\x%s\x%s\x%s\x%s\x%s' % (str01, str02, str03,
sttr04, str05, str06))*16, ('192.168.1.255', 80))

Iain

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diffuser78 at gmail

Jun 28, 2006, 8:56 AM

Post #4 of 13 (382 views)
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Re: String Question [In reply to]

Many Thanks!! It worked like a charm.

Fredrik Lundh wrote:
> diffuser78[at]gmail.com wrote:
>
> > mac_string = '001485e55503' (This is the mac address of a computer.)
> >
> > I am using wake on LAN python script to start computer remote.It uses
> > format like this ....
> >
> > s.sendto('\xff'*6 + '\x00\x014\x85\xe5\x55\x03'*16, ('192.168.1.255',
> > 80))
> >
> > where '\x00\x14\x85\xe5\x55\x03' is the MAC address to be used.
>
> s.sendto('\xff'*6 + binascii.unhexlify(mac_string) *16, ('192.168.1.255', 80))
>
> </F>

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diffuser78 at gmail

Jun 28, 2006, 8:59 AM

Post #5 of 13 (382 views)
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Re: String Question [In reply to]

I will try this one too...thanks for your response.
Iain King wrote:
> diffuser78[at]gmail.com wrote:
> > mac_string = '001485e55503' (This is the mac address of a computer.)
> >
> > I am using wake on LAN python script to start computer remote.It uses
> > format like this ....
> >
> > s.sendto('\xff'*6 + '\x00\x014\x85\xe5\x55\x03'*16, ('192.168.1.255',
> > 80))
> >
> > where '\x00\x14\x85\xe5\x55\x03' is the MAC address to be used.
> >
> >
> > What I do is break the string into 6 parts like this,
> >
> > str01=mac_string[0:2]
> > str02=mac_string[2:4]
> > str03=mac_string[4:6]
> > str04=mac_string[6:8]
> > str05=mac_string[8:10]
> > str06=mac_string[10:12]
> >
> > and if I use it like this
> >
> > s.sendto('\xff'*6 + '\xstr01\xstr02\xstr03\xstr04\xstr05\xstr06'*16,
> > ('192.168.1.255', 80))
> > I get an error
> >
> >
> > I also tried like this
> > s.sendto('\xff'*6 + 'mac_string'*16, ('192.168.1.255', 80))
> >
> > Thiis also didnt work.
> >
> >
> > Since the MAC adddress are hexadecimal, how should I go about it here.
> >
> > Please help, every help is appreciated. Thanks
>
> See http://docs.python.org/lib/typesseq-strings.html
>
> You probably want:
>
> s.sendto('\xff'*6 + ('\x%s\x%s\x%s\x%s\x%s\x%s' % (str01, str02, str03,
> sttr04, str05, str06))*16, ('192.168.1.255', 80))
>
> Iain

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martin at v

Jun 28, 2006, 9:38 AM

Post #6 of 13 (382 views)
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Re: String Question [In reply to]

diffuser78[at]gmail.com wrote:
> mac_string = '001485e55503' (This is the mac address of a computer.)
> Since the MAC adddress are hexadecimal, how should I go about it here.
>
> Please help, every help is appreciated. Thanks

I could not quite understand what you are trying to achieve, but
it appears that you want to convert a character strings of hexadecimal
characters into a byte string with the same bytes. I recommend this:

py> import binascii
py> binascii.a2b_hex("001485e55503")
'\x00\x14\x85\xe5U\x03'

Of course, if the string is fixed, you could just as well use the
result string (i.e. '\x00\x14\x85\xe5U\x03') directly.

Regards,
Martin
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timr at probo

Jun 29, 2006, 11:57 PM

Post #7 of 13 (381 views)
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Re: String Question [In reply to]

"Iain King" <iainking[at]gmail.com> wrote:
>
>You probably want:
>
>s.sendto('\xff'*6 + ('\x%s\x%s\x%s\x%s\x%s\x%s' % (str01, str02, str03,
> sttr04, str05, str06))*16, ('192.168.1.255', 80))

You probably should TRY suggestions before you post them. That will get an
"invalid \x escape". \x must be followed by exactly two hex digits. You
can't build up an escape sequence like this.
--
- Tim Roberts, timr[at]probo.com
Providenza & Boekelheide, Inc.
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iainking at gmail

Jun 30, 2006, 1:09 AM

Post #8 of 13 (378 views)
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Re: String Question [In reply to]

Tim Roberts wrote:
> "Iain King" <iainking[at]gmail.com> wrote:
> >
> >You probably want:
> >
> >s.sendto('\xff'*6 + ('\x%s\x%s\x%s\x%s\x%s\x%s' % (str01, str02, str03,
> > sttr04, str05, str06))*16, ('192.168.1.255', 80))
>
> You probably should TRY suggestions before you post them. That will get an
> "invalid \x escape". \x must be followed by exactly two hex digits. You
> can't build up an escape sequence like this.
> --
> - Tim Roberts, timr[at]probo.com
> Providenza & Boekelheide, Inc.

You're right. I'd foolishly assumed that \x was just another character
code, like \t or \n. Apologies.

Iain

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root at sys1

Jun 23, 2008, 7:54 AM

Post #9 of 13 (329 views)
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Re: String question [In reply to]

Wow...about ten seconds to get a kind response ....
Thanks Tim.

Andrew.

Tim Golden wrote:
> Andreu wrote:
>> I want to split a sentence and assign each word to a variable.
>> In Ruby I can do it as:
>>
>> v1,v2,v3,v4,v5 = str1.split
>>
>> Which will be the Python equivalent ? Thanks.
>
> That would be:
>
> str1 = "The quick brown fox jumps"
> v1, v2, v3, v4, v5 = str1.split ()
>
> TJG
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root at sys1

Jun 23, 2008, 3:13 PM

Post #10 of 13 (318 views)
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Re: String question [In reply to]

Yes, ... don't ask me why, but in fact v1,v2,v3 = str1.split()
does not seem to work. My original problem was I forgot about
the parenthesis as Tim point out. So I ended up converting to a
list as in: v = str1.split() and accessing the elements using
v[0] v[1] ect...it is working now. Thanks.

Andreu.

cokofreedom[at]gmail.com wrote:
> However I would make a list of it.
>>>> v_list = example.split()
> That seems to me to be the more pythonic way to do it, since it is
> dynamic.
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M8R-yfto6h at mailinator

Jun 23, 2008, 8:38 PM

Post #11 of 13 (314 views)
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Re: String question [In reply to]

"Andreu" <root[at]sys1.org> wrote in message news:g3p72i$432$1[at]aioe.org...
> Yes, ... don't ask me why, but in fact v1,v2,v3 = str1.split()
> does not seem to work. My original problem was I forgot about
> the parenthesis as Tim point out. So I ended up converting to a
> list as in: v = str1.split() and accessing the elements using
> v[0] v[1] ect...it is working now. Thanks.
>
> Andreu.

v1,v2,v3 = str1.split() will only work if there are exactly three things in
str1.

>>> s = 'this is a test'
>>> v1,v2,v3 = s.split()
Traceback (most recent call last):
File "<interactive input>", line 1, in <module>
ValueError: too many values to unpack
>>> v1,v2,v3 = s.split(' ',2) # limit to two splits maximum
>>> v1
'this'
>>> v2
'is'
>>> v3
'a test'

-Mark

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cokofreedom at gmail

Jun 24, 2008, 12:53 AM

Post #12 of 13 (312 views)
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Re: String question [In reply to]

On Jun 24, 5:38 am, "Mark Tolonen" <M8R-yft...@mailinator.com> wrote:
> "Andreu" <r...@sys1.org> wrote in messagenews:g3p72i$432$1[at]aioe.org...
> > Yes, ... don't ask me why, but in fact v1,v2,v3 = str1.split()
> > does not seem to work. My original problem was I forgot about
> > the parenthesis as Tim point out. So I ended up converting to a
> > list as in: v = str1.split() and accessing the elements using
> > v[0] v[1] ect...it is working now. Thanks.
>
> > Andreu.
>
> v1,v2,v3 = str1.split() will only work if there are exactly three things in
> str1.
>
> >>> s = 'this is a test'
> >>> v1,v2,v3 = s.split()
>
> Traceback (most recent call last):
> File "<interactive input>", line 1, in <module>
> ValueError: too many values to unpack>>> v1,v2,v3 = s.split(' ',2) # limit to two splits maximum
> >>> v1
> 'this'
> >>> v2
> 'is'
> >>> v3
>
> 'a test'
>
> -Mark

In Python 3k I believe you can put a * next to one of the variables to
hold multiple arguments. That'll be aidful!
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tjreedy at udel

Jun 24, 2008, 11:40 AM

Post #13 of 13 (311 views)
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Re: String question [In reply to]

cokofreedom[at]gmail.com wrote:
> On Jun 24, 5:38 am, "Mark Tolonen" <M8R-yft...@mailinator.com> wrote:

> In Python 3k I believe you can put a * next to one of the variables to
> hold multiple arguments. That'll be aidful!

IDLE 3.0b1
>>> a,b,*c=[1,2,3,4,5]
>>> c
[3, 4, 5]
>>> a,*b,c = [1,2,3,4,5]
>>> b
[2, 3, 4]
>>> a,b,*c=[1,2]
>>> c
[]

Augmented assignment is quite similar to argument passing:
at most one starred target;
at least as many items as un-starred targets (as now).

tjr

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