
s.havemann at tu-bs
Apr 26, 1999, 10:36 AM
Post #1 of 1
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SOLUTION: Triangulation of the unit sphere
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Hi! === I have a neat C++ solution for the problem of finding a triangulation of n random points distributed on the unit sphere. The algorithm runs in O(n*sqrt(n)) with a nice small constant, as you can see below (SGI O2 with 250 MHz MIPS R10000). Python (www.python.org) and PyOpenGL (http://starship.python.net/crew/da/PyOpenGL/) have been _very_ helpful, and there's a nice unit sphere viewer and algorithm visualization included in the 8K .tgz for those unixers who have it installed (I can build a windows VC++ version on demand). Have a look: ftp://ftp.cg.cs.tu-bs.de/pub/cg/people/havemann/sdelaunay-1.00.tgz Greetings, Sven. =============================================================== 1004 faces, 504 vertices, 0.065275 seconds 2004 faces, 1004 vertices, 0.138277 seconds 3004 faces, 1504 vertices, 0.213124 seconds 4004 faces, 2004 vertices, 0.323524 seconds 5004 faces, 2504 vertices, 0.416665 seconds 6004 faces, 3004 vertices, 0.520598 seconds 7004 faces, 3504 vertices, 0.655553 seconds 8004 faces, 4004 vertices, 0.757154 seconds 9004 faces, 4504 vertices, 0.887238 seconds 10004 faces, 5004 vertices, 1.024282 seconds 11004 faces, 5504 vertices, 1.160054 seconds 12004 faces, 6004 vertices, 1.327187 seconds 13004 faces, 6504 vertices, 1.466274 seconds 14004 faces, 7004 vertices, 1.627190 seconds 15004 faces, 7504 vertices, 1.818125 seconds 16004 faces, 8004 vertices, 1.988085 seconds 17004 faces, 8504 vertices, 2.169752 seconds 18004 faces, 9004 vertices, 2.370354 seconds 19004 faces, 9504 vertices, 2.549433 seconds 20004 faces, 10004 vertices, 2.751907 seconds -- __________________________________________________________________ dipl-inform. Sven Havemann Institut fuer ComputerGraphik Odastrasse 6 Rebenring 18 38122 Braunschweig - Germany 38106 Braunschweig - Germany Tel. 0531/2808955 Tel. 0531/391-2108, Fax: -2103 mailto:s.havemann [at] tu-bs http://www.cg.cs.tu-bs.de
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